10x^2(y^2)-19xy+6=

Solution for 10x^2(y^2)-19xy+6= equation:

Simplifying
10x2(y2) + -19xy + 6 = 0

Multiply x2 * y2
10x2y2 + -19xy + 6 = 0

Reorder the terms:
6 + -19xy + 10x2y2 = 0

Solving
6 + -19xy + 10x2y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(2 + -5xy)(3 + -2xy) = 0

Subproblem 1
Set the factor '(2 + -5xy)' equal to zero and attempt to solve:

Simplifying
2 + -5xy = 0

Solving
2 + -5xy = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -5xy = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -5xy = 0 + -2
-5xy = 0 + -2

Combine like terms: 0 + -2 = -2
-5xy = -2

Divide each side by '-5y'.
x = 0.4y-1

Simplifying
x = 0.4y-1
Subproblem 2
Set the factor '(3 + -2xy)' equal to zero and attempt to solve:

Simplifying
3 + -2xy = 0

Solving
3 + -2xy = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2xy = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2xy = 0 + -3
-2xy = 0 + -3

Combine like terms: 0 + -3 = -3
-2xy = -3

Divide each side by '-2y'.
x = 1.5y-1

Simplifying
x = 1.5y-1
Solution
x = {0.4y-1, 1.5y-1}